给定一个二叉树的 根节点 root,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
示例 1:
输入: [1,2,3,null,5,null,4]
输出: [1,3,4]
示例 2:
输入:[1,null,3]
输出: [1,3]
示例 3:
输入: []
输出: []
提示:
- 二叉树的节点个数的范围是 [0,100]
- -100 <= Node.val <= 100
Python 解答:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def rightSideView(self, root: TreeNode) -> List[int]:
res = []
if not root:
return res
queue = [root]
while queue:
res.append(queue[0].val)
level = []
for i in range(len(queue)):
if queue[i].right:
level.append(queue[i].right)
if queue[i].left:
level.append(queue[i].left)
queue = level
return res
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