给定两个整数,分别表示分数的分子 numerator 和分母 denominator,以 字符串形式返回小数 。
如果小数部分为循环小数,则将循环的部分括在括号内。
如果存在多个答案,只需返回 任意一个 。
对于所有给定的输入,保证 答案字符串的长度小于 104 。
示例 1:
输入:numerator = 1, denominator = 2
输出:"0.5"
示例 2:
输入:numerator = 2, denominator = 1
输出:"2"
示例 3:
输入:numerator = 2, denominator = 3
输出:"0.(6)"
示例 4:
输入:numerator = 4, denominator = 333
输出:"0.(012)"
示例 5:
输入:numerator = 1, denominator = 5
输出:"0.2"
提示:
- -2^31 <= numerator, denominator <= 2^31 – 1
- denominator != 0
Python 解答:
class Solution:
def fractionToDecimal(self, numerator: int, denominator: int) -> str:
adic = {}
index = 0
is_posivite = True
if (numerator > 0 and denominator < 0) or (numerator < 0 and denominator > 0):
is_posivite = False
numerator, denominator = abs(numerator), abs(denominator)
interger = numerator//denominator
remainder = numerator % denominator
pre = str(interger)
if not is_posivite:
pre = '-' + pre
if remainder > 0:
pre += '.'
nex = []
is_repeated = -1
while remainder > 0:
if remainder not in adic.keys():
adic[remainder] = index
index += 1
else:
is_repeated = adic[remainder]
break
numerator = remainder*10
interger, remainder = divmod(numerator, denominator)
nex.append(str(interger))
if len(nex)+len(pre) >= 10**4:
break
result = ''
if is_repeated != -1:
nex.insert(is_repeated, '(' )
result = pre+''.join(nex)+')'
else:
result = pre+''.join(nex)
return result
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