不使用任何内建的哈希表库设计一个哈希集合(HashSet)。
实现 MyHashSet 类:
void add(key) 向哈希集合中插入值 key 。
bool contains(key) 返回哈希集合中是否存在这个值 key 。
void remove(key) 将给定值 key 从哈希集合中删除。如果哈希集合中没有这个值,什么也不做。
示例:
输入:
["MyHashSet", "add", "add", "contains", "contains", "add", "contains", "remove", "contains"]
[[], [1], [2], [1], [3], [2], [2], [2], [2]]
输出:
[null, null, null, true, false, null, true, null, false]
解释:
MyHashSet myHashSet = new MyHashSet();
myHashSet.add(1); // set = [1]
myHashSet.add(2); // set = [1, 2]
myHashSet.contains(1); // 返回 True
myHashSet.contains(3); // 返回 False ,(未找到)
myHashSet.add(2); // set = [1, 2]
myHashSet.contains(2); // 返回 True
myHashSet.remove(2); // set = [1]
myHashSet.contains(2); // 返回 False ,(已移除)
提示:
- 0 <= key <= 106
- 最多调用 10^4 次 add、remove 和 contains 。
进阶:你可以不使用内建的哈希集合库解决此问题吗?
Python 解答:
class MyHashSet:
class Node:
def __init__(self, val):
self.val = val
self.next = None
def __init__(self):
"""
Initialize your data structure here.
"""
self.stack = [None for i in range(1010)]
self.base = 1009
def add(self, key: int) -> None:
index = key % self.base
if not self.stack[index]:
self.stack[index] = self.Node(key)
else:
p = self.stack[index]
if p.val == key:
return
while p.next:
p = p.next
if p.val == key:
return
p.next = self.Node(key)
def remove(self, key: int) -> None:
index = key % self.base
p = self.stack[index]
if p:
if p.val == key:
self.stack[index] = p.next
else:
pre = p
p = p.next
while p:
if p.val == key:
pre.next = p.next
break
pre = p
p = p.next
def contains(self, key: int) -> bool:
"""
Returns true if this set contains the specified element
"""
index = key % self.base
p = self.stack[index]
while p:
if p.val == key:
return True
p = p.next
return False
# Your MyHashSet object will be instantiated and called as such:
# obj = MyHashSet()
# obj.add(key)
# obj.remove(key)
# param_3 = obj.contains(key)
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