Given an array of positive integers nums, return the maximum possible sum of an ascending subarray in nums.
A subarray is defined as a contiguous sequence of numbers in an array.
A subarray [numsl, numsl+1, …, numsr-1, numsr] is ascending if for all i where l <= i < r, numsi < numsi+1. Note that a subarray of size 1 is ascending.
Example 1:
Input: nums = [10,20,30,5,10,50]
Output: 65
Explanation: [5,10,50] is the ascending subarray with the maximum sum of 65.
Example 2:
Input: nums = [10,20,30,40,50]
Output: 150
Explanation: [10,20,30,40,50] is the ascending subarray with the maximum sum of 150.
Example 3:
Input: nums = [12,17,15,13,10,11,12]
Output: 33
Explanation: [10,11,12] is the ascending subarray with the maximum sum of 33.
Example 4:
Input: nums = [100,10,1]
Output: 100
Constraints:
- 1 <= nums.length <= 100
- 1 <= nums[i] <= 100
Solution in python:
class Solution:
def maxAscendingSum(self, nums: List[int]) -> int:
max_value = 0
pre = 0
total = 0
for i in range(len(nums)):
if nums[i] > pre:
total += nums[i]
pre = nums[i]
else:
total = nums[i]
pre = nums[i]
if total > max_value:
max_value = total
return max_value
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