Given an array of integers nums, you start with an initial positive value startValue.

In each iteration, you calculate the step by step sum of startValue plus elements in nums (from left to right).

Return the minimum positive value of startValue such that the step by step sum is never less than 1.

Example 1:
Input: nums = [-3,2,-3,4,2]
Output: 5
Explanation: If you choose startValue = 4, in the third iteration your step by step sum is less than 1.
step by step sum

startValue = 4 startValue = 5 nums
(4 -3 ) = 1 (5 -3 ) = 2 -3
(1 +2 ) = 3 (2 +2 ) = 4 2
(3 -3 ) = 0 (4 -3 ) = 1 -3
(0 +4 ) = 4 (1 +4 ) = 5 4
(4 +2 ) = 6 (5 +2 ) = 7 2

Example 2:
Input: nums = [1,2]
Output: 1
Explanation: Minimum start value should be positive.

Example 3:
Input: nums = [1,-2,-3]
Output: 5

Constraints:

  • 1 <= nums.length <= 100
  • -100 <= nums[i] <= 100

Solution in python:

class Solution:
    def minStartValue(self, nums: List[int]) -> int:
        min_c = 0
        result = 0
        for item in nums:
            result += item
            if min_c > result:
                min_c = result
        return 1-min_c
最后修改日期: 2021年3月14日

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