Given an integer n. Each number from 1 to n is grouped according to the sum of its digits.
Return how many groups have the largest size.
Example 1:
Input: n = 13
Output: 4
Explanation: There are 9 groups in total, they are grouped according sum of its digits of numbers from 1 to 13:
[1,10], [2,11], [3,12], [4,13], [5], [6], [7], [8], [9]. There are 4 groups with largest size.
Example 2:
Input: n = 2
Output: 2
Explanation: There are 2 groups [1], [2] of size 1.
Example 3:
Input: n = 15
Output: 6
Example 4:
Input: n = 24
Output: 5
Constraints:
- 1 <= n <= 10^4
Solution in python:
class Solution:
def countLargestGroup(self, n: int) -> int:
def count(num):
c = 0
while num > 0:
num, r = divmod(num, 10)
c += r
return c
adic = dict()
for i in range(1, n+1):
s = count(i)
if s not in adic.keys():
adic[s] = 1
else:
adic[s] += 1
max_v = max(adic.values())
result = 0
for item in adic.values():
if item == max_v:
result += 1
return result
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