Given an integer array sorted in non-decreasing order, there is exactly one integer in the array that occurs more than 25% of the time.
Return that integer.
Example 1:
Input: arr = [1,2,2,6,6,6,6,7,10]
Output: 6
Constraints:
- 1 <= arr.length <= 10^4
- 0 <= arr[i] <= 10^5
Solution in python:
class Solution:
def findSpecialInteger(self, arr: List[int]) -> int:
adic = dict()
for item in arr:
if item not in adic.keys():
adic[item] = 1
else:
adic[item] += 1
if adic[item] > len(arr)*0.25:
return item
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