Given an array of integers arr, return true if and only if it is a valid mountain array.
Recall that arr is a mountain array if and only if:
- arr.length >= 3
- There exists some i with 0 < i < arr.length – 1 such that:
- arr[0] < arr[1] < … < arr[i – 1] < arr[i]
- arr[i] > arr[i + 1] > … > arr[arr.length – 1]
Example 1:
Input: arr = [2,1]
Output: false
Example 2:
Input: arr = [3,5,5]
Output: false
Example 3:
Input: arr = [0,3,2,1]
Output: true
Constraints:
- 1 <= arr.length <= 10^4
- 0 <= arr[i] <= 10^4
Solution in python:
class Solution:
def validMountainArray(self, arr: List[int]) -> bool:
i = 0
j = len(arr)-1
if j < 2 or arr[1] < arr[0] or arr[-1] > arr[-2]:
return False
while i < len(arr):
if arr[i+1] > arr[i]:
i += 1
else: break
while j > 0:
if arr[j-1] > arr[j]:
j -= 1
else: break
return i == j
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