937. Reorder Data in Log Files-重新排列日志文件

You are given an array of logs. Each log is a space-delimited string of words, where the first word is the identifier.

There are two types of logs:

• Letter-logs: All words (except the identifier) consist of lowercase English letters.
• Digit-logs: All words (except the identifier) consist of digits.
  Reorder these logs so that:
  1. The letter-logs come before all digit-logs.
  2. The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.
  3. The digit-logs maintain their relative ordering.

Return the final order of the logs.

Example 1:
Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
Explanation:
The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".

Example 2:
Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]

Constraints:

• 1 <= logs.length <= 100
• 3 <= logs[i].length <= 100
• All the tokens of logs[i] are separated by a single space.
• logs[i] is guaranteed to have an identifier and at least one word after the identifier.

Solution in python:

class Solution:
    def reorderLogFiles(self, logs: List[str]) -> List[str]:

        letlist = []
        diglist = []
        for item in logs:
            label, content = item.split(' ', 1)
            if content[0].isalpha():
                temp = " "*(100-len(content))
                letlist.append(content+temp+label)
            else:
                diglist.append(item)
        letlist.sort()
        for i in range(len(letlist)):
            left, right = letlist[i].rsplit(' ', 1)
            left = left.rstrip()
            letlist[i] = right+" "+left
        letlist.extend(diglist)
        return letlist