In a string s of lowercase letters, these letters form consecutive groups of the same character.
For example, a string like s = "abbxxxxzyy" has the groups "a", "bb", "xxxx", "z", and "yy".
A group is identified by an interval [start, end], where start and end denote the start and end indices (inclusive) of the group. In the above example, "xxxx" has the interval [3,6].
A group is considered large if it has 3 or more characters.
Return the intervals of every large group sorted in increasing order by start index.
Example 1:
Input: s = "abbxxxxzzy"
Output: [[3,6]]
Explanation: "xxxx" is the only large group with start index 3 and end index 6.
Example 2:
Input: s = "abc"
Output: []
Explanation: We have groups "a", "b", and "c", none of which are large groups.
Example 3:
Input: s = "abcdddeeeeaabbbcd"
Output: [[3,5],[6,9],[12,14]]
Explanation: The large groups are "ddd", "eeee", and "bbb".
Example 4:
Input: s = "aba"
Output: []
Constraints:
- 1 <= s.length <= 1000
- s contains lower-case English letters only.
Solution in python:
class Solution:
def largeGroupPositions(self, s: str) -> List[List[int]]:
result = []
prior = s[0]
count = 0
i = 0
while i < len(s):
j = i
while j < len(s):
if s[j] == prior:
count += 1
j += 1
else:
break
if j != len(s):
prior = s[j]
if count >= 3:
result.append([i, j-1])
i = j
count = 0
return result
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