Given a binary tree, return the bottom-up level order traversal of its nodes’ values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree [3,9,20,null,null,15,7],
return its bottom-up level order traversal as:
Solution in python:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def levelOrderBottom(self, root: TreeNode) -> List[List[int]]:
if root == None:
return []
result = []
level = []
queue = [root]
size = 1
num = 0
while size > 0:
temp = queue.pop(0)
level.append(temp.val)
size -= 1
if temp.left:
queue.append(temp.left)
num += 1
if temp.right:
queue.append(temp.right)
num += 1
if size == 0:
result.insert(0, level)
size = num
num = 0
level = []
return result
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