给定两个二叉树,编写一个函数来检验它们是否相同。
如果两个树在结构上相同,并且节点具有相同的值,则认为它们是相同的。
Given the roots of two binary trees p and q, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
Example 1:
Input: p = [1,2,3], q = [1,2,3]
Output: true
Example 2:
Input: p = [1,2], q = [1,null,2]
Output: false
Example 3:
Input: p = [1,2,1], q = [1,1,2]
Output: false
Constraints:
- The number of nodes in both trees is in the range [0, 100].
-10^4 <= Node.val <= 10^4
Solution in python:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isSameTree(self, p: TreeNode, q: TreeNode) -> bool:
if p == None and q == None:
return True
elif (p and q == None) or (p == None and q):
return False
elif p.val != q.val:
return False
else:
left_p, right_p = p.left, p.right
left_q, right_q = q.left, q.right
return self.isSameTree(left_p, left_q) and self.isSameTree(right_p, right_q)
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