Given the head of a sorted linked list, delete all duplicates such that each element appears only once. Return the linked list sorted as well.
Example 1:
Input: head = [1,1,2]
Output: [1,2]
Example 2:
Input: head = [1,1,2,3,3]
Output: [1,2,3]
Constraints:
- The number of nodes in the list is in the range [0, 300].
-100 <= Node.val <= 100
- The list is guaranteed to be sorted in ascending order.
Solution in python:
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def deleteDuplicates(self, head: ListNode) -> ListNode:
if head == None:
return None
first = ListNode(head.val)
pre = first
while head != None:
if pre.val == head.val:
pre.next = head.next
head = head.next
else:
pre = head
head = head.next
return first
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