输入一个链表,输出该链表中倒数第k个节点。为了符合大多数人的习惯,本题从1开始计数,即链表的尾节点是倒数第1个节点。
例如,一个链表有 6 个节点,从头节点开始,它们的值依次是 1、2、3、4、5、6。这个链表的倒数第 3 个节点是值为 4 的节点。
示例:
给定一个链表: 1->2->3->4->5, 和 k = 2.
返回链表 4->5.
Python 解答:
1.直觉方法
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def getKthFromEnd(self, head: ListNode, k: int) -> ListNode:
count = 0
p = head
while p:
count += 1
p = p.next
num = count - k
i = 1
while i <= num:
head = head.next
i += 1
return head
1.双指针
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def getKthFromEnd(self, head: ListNode, k: int) -> ListNode:
count = 0
p = head
while count < k:
p = p.next
count += 1
while p:
head = head.next
p = p.next
return head
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