You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.
Two strings are alike if they have the same number of vowels (‘a’, ‘e’, ‘i’, ‘o’, ‘u’, ‘A’, ‘E’, ‘I’, ‘O’, ‘U’). Notice that s contains uppercase and lowercase letters.
Return true if a and b are alike. Otherwise, return false.
Example 1:
Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:
Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.
Example 3:
Input: s = "MerryChristmas"
Output: false
Example 4:
Input: s = "AbCdEfGh"
Output: true
Constraints:
- 2 <= s.length <= 1000
- s.length is even.
- s consists of uppercase and lowercase letters.
Solution in python:
class Solution:
def halvesAreAlike(self, s: str) -> bool:
aset = set(['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'])
c_a = 0
c_b = 0
length = len(s)//2
for i in range(length):
if s[i] in aset:
c_a += 1
if s[i+length] in aset:
c_b += 1
return c_a == c_b
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