You are given a string allowed consisting of distinct characters and an array of strings words. A string is consistent if all characters in the string appear in the string allowed.
Return the number of consistent strings in the array words.
Example 1:
Input: allowed = "ab", words = ["ad","bd","aaab","baa","badab"]
Output: 2
Explanation: Strings "aaab" and "baa" are consistent since they only contain characters ‘a’ and ‘b’.
Example 2:
Input: allowed = "abc", words = ["a","b","c","ab","ac","bc","abc"]
Output: 7
Explanation: All strings are consistent.
Example 3:
Input: allowed = "cad", words = ["cc","acd","b","ba","bac","bad","ac","d"]
Output: 4
Explanation: Strings "cc", "acd", "ac", and "d" are consistent.
Constraints:
- 1 <= words.length <= 104
- 1 <= allowed.length <= 26
- 1 <= words[i].length <= 10
- The characters in allowed are distinct.
- words[i] and allowed contain only lowercase English letters.
Solution in python:
class Solution:
def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
allowset = set(allowed)
count = 0
for word in words:
for char in word:
if char in allowset:
continue
else:
break
else:
count += 1
return count
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