You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array code of length of n and a key k.

To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.

If k > 0, replace the ith number with the sum of the next k numbers.
If k < 0, replace the ith number with the sum of the previous k numbers.
If k == 0, replace the ith number with 0.
As code is circular, the next element of code[n-1] is code[0], and the previous element of code[0] is code[n-1].

Given the circular array code and an integer key k, return the decrypted code to defuse the bomb!

Example 1:
Input: code = [5,7,1,4], k = 3
Output: [12,10,16,13]
Explanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.

Example 2:
Input: code = [1,2,3,4], k = 0
Output: [0,0,0,0]
Explanation: When k is zero, the numbers are replaced by 0.

Example 3:
Input: code = [2,4,9,3], k = -2
Output: [12,5,6,13]
Explanation: The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.

Constraints:

  • n == code.length
  • 1 <= n <= 100
  • 1 <= code[i] <= 100
  • -(n – 1) <= k <= n – 1

Solution in python:

class Solution:
    def decrypt(self, code: List[int], k: int) -> List[int]:
        result = [0 for i in range(len(code))]
        if k == 0:
            for i in range(len(code)):
                code[i] = 0 
        elif k > 0:
            for i in range(len(code)):
                temp = 0 
                j = i+1
                while j < i+k+1:
                    temp += code[j%len(code)]
                    j += 1
                result[i] = temp
        else:
            for i in range(len(code)):
                temp = 0 
                j = i-1
                while j > i+k-1:
                    temp += code[(j+len(code))%len(code)]
                    j -= 1
                result[i] = temp

        return result
最后修改日期: 2021年3月21日

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