1646. Get Maximum in Generated Array-获取生成数组中的最大值

You are given an integer n. An array nums of length n + 1 is generated in the following way:
nums[0] = 0
nums[1] = 1
nums[2 i] = nums[i] when 2 <= 2 i <= n
nums[2 i + 1] = nums[i] + nums[i + 1] when 2 <= 2 i + 1 <= n

Return the maximum integer in the array nums.

Example 1:
Input: n = 7
Output: 3
Explanation: According to the given rules:
nums[0] = 0
nums[1] = 1
nums[(1 2) = 2] = nums[1] = 1
nums[(1 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
nums[(2 2) = 4] = nums[2] = 1
nums[(2 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
nums[(3 2) = 6] = nums[3] = 2
nums[(3 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3.

Example 2:
Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums[0], nums[1], and nums[2] is 1.

Example 3:
Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums[0], nums[1], nums[2], and nums[3] is 2.

Constraints:

• 0 <= n <= 100

Solution in python:

class Solution:
    def getMaximumGenerated(self, n: int) -> int:
        if n <=1 :
            return n
        nums = [0 for i in range(n+1)]
        nums[0] = 0
        nums[1] = 1
        for i in range(2, n+1):
            if i % 2 == 0:
                nums[i] = nums[i//2]
            else:
                nums[i] = nums[i//2]+nums[i//2+1]
        return max(nums)