Given two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).
Example 1:
Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].
Example 2:
Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].
Constraints:
- 0 <= low <= high <= 10^9
Solution in python:
class Solution:
def countOdds(self, low: int, high: int) -> int:
if high % 2 == 1:
return (high-low)//2 + 1
else:
return (high+1-low)//2
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