1507. Reformat Date-转变日期格式

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", …, "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

Example 1:
Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:
Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:
Input: date = "26th May 1960"
Output: "1960-05-26"

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Solution in python:

class Solution:
    def reformatDate(self, date: str) -> str:
        month = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"]
        dates = date.split()
        day = None
        if len(dates[0]) == 4:
            day = dates[0][:2]
        else:
            day = "0" + dates[0][0]
        mon = str(month.index(dates[1])+1 )   
        if len(mon) < 2:
            mon = "0" + mon
        year = dates[2]
        result = year + "-" + mon + "-" + day
        return result