International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-…", "c" maps to "-.-.", and so on.
For convenience, the full table for the 26 letters of the English alphabet is given below:
[".-","-…","-.-.","-..",".","..-.","–.","….","..",".—","-.-",".-..","–","-.","—",".–.","–.-",".-.","…","-","..-","…-",".–","-..-","-.–","–.."]
Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cab" can be written as "-.-..–…", (which is the concatenation "-.-." + ".-" + "-…"). We’ll call such a concatenation, the transformation of a word.
Return the number of different transformations among all words we have.
Example:
Input: words = ["gin", "zen", "gig", "msg"]
Output: 2
Explanation:
The transformation of each word is:
"gin" -> "–…-."
"zen" -> "–…-."
"gig" -> "–…–."
"msg" -> "–…–."
There are 2 different transformations, "–…-." and "–…–.".
Note:
- The length of words will be at most 100.
- Each words[i] will have length in range [1, 12].
- words[i] will only consist of lowercase letters.
Solution in python:
class Solution:
def uniqueMorseRepresentations(self, words: List[str]) -> int:
codes = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
aset = set()
result = ""
for word in words:
for char in word:
result += codes[ord(char)-97]
aset.add(result)
result = ""
return len(aset)
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