Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values.
Example 1:
Input: n = 5
Output: true
Explanation: The binary representation of 5 is: 101
Example 2:
Input: n = 7
Output: false
Explanation: The binary representation of 7 is: 111.
Example 3:
Input: n = 11
Output: false
Explanation: The binary representation of 11 is: 1011.
Example 4:
Input: n = 10
Output: true
Explanation: The binary representation of 10 is: 1010.
Example 5:
Input: n = 3
Output: false
Constraints:
1 <= n <= 2^31 - 1
Solution in python:
class Solution:
def hasAlternatingBits(self, n: int) -> bool:
prior = n & 1
n >>= 1
while n > 0:
temp = n & 1
n >>= 1
if temp != prior:
prior = temp
continue
else:
return False
return True
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