Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
You may assume that the array is non-empty and the majority element always exist in the array.
Example 1:
Input: [3,2,3]
Output: 3
Example 2:
Input: [2,2,1,1,1,2,2]
Output: 2
Solution in python:
class Solution:
def majorityElement(self, nums: List[int]) -> int:
length = len(nums)//2
element = {}
for item in nums:
if not item in element.keys():
element[item] = 1
else:
element[item] += 1
if element[item] > length:
return item
Complexity analysis:
- Time complexity:
O(N)
- Space complexity:
O(N)
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