Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1
Example 2:
Input: [4,1,2,1,2]
Output: 4
Solution in python:
class Solution:
def singleNumber(self, nums: List[int]) -> int:
for i in range(1, len(nums)):
nums[0] ^= nums[i]
return nums[0]
Complexity analysis:
- Time complexity:
O(N)
- Space complexity:
None
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